q^3-q^2-q-1/8=0

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Solution for q^3-q^2-q-1/8=0 equation:


q in (-oo:+oo)

q^3-q^2-q-(1/8) = 0

q^3-q^2-q-1/8 = 0

q^3-q^2-q-1/8 = 0

q^3-q^2-q-1/8 = 0 // * 0

{ 1, -1 }

1

q = 1

8*q^3-8*q^2-8*q-1 = -9

1

-1

q = -1

8*q^3-8*q^2-8*q-1 = -9

-1

{ 1/2, -1/2, 1/4, -1/4, 1/8, -1/8, -1/2, 1/2, -1/4, 1/4, -1/8, 1/8 }

1/2

q

1/2

8*q^3-8*q^2-8*q-1 = -6

1/2

-1/2

q

-1/2

8*q^3-8*q^2-8*q-1 = 0

-1/2

q+1/2

8*q^2-12*q-2

8*q^3-8*q^2-8*q-1

q+1/2

-8*q^3-4*q^2

-12*q^2-8*q-1

12*q^2+6*q

-2*q-1

2*q+1

0

8*q^2-12*q-2 = 0

DELTA = (-12)^2-(-2*4*8)

DELTA = 208

DELTA > 0

q = (208^(1/2)+12)/(2*8) or q = (12-208^(1/2))/(2*8)

q = (4*13^(1/2)+12)/16 or q = (12-4*13^(1/2))/16

q in { (12-4*13^(1/2))/16, (4*13^(1/2)+12)/16, -1/2}

q in { (12-4*13^(1/2))/16, (4*13^(1/2)+12)/16, -1/2 }

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